(A) Phase $1$: Free fall for $t_1 = 10\,s$ with $u_1 = 0$ and $a_1 = g = 10\,m/s^2$.Velocity at the end of free fall: $v_1 = u_1 + a_1 t_1 = 0 + 10 \t

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(A) Phase $1$: Free fall for $t_1 = 10\,s$ with $u_1 = 0$ and $a_1 = g = 10\,m/s^2$.Velocity at the end of free fall: $v_1 = u_1 + a_1 t_1 = 0 + 10 \times 10 = 100\,m/s$.Distance covered during free fall: $h_1 = u_1 t_1 + \frac{1}{2} a_1 t_1^2 = 0 + \frac{1}{2} \times 10 \times (10)^2 = 500\,m$.Phase $2$: Parachute opens,retardation $a_2 = -2.5\,m/s^2$. Initial velocity $u_2 = 100\,m/s$.Remaining height: $h_2 = 2495 - 500 = 1995\,m$.Using $v_2^2 = u_2^2 + 2 a_2 h_2$:$v_2^2 = (100)^2 + 2 \times (-2.5) \times 1995$$v_2^2 = 10000 - 9975 = 25$$v_2 = \sqrt{25} = 5\,m/s$.

Class 11 Physics Motion in Straight Line Mix Examples-Motion in Straight Line

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$A$ parachutist drops freely from an aeroplane for $10\,s$ before the parachute opens. Then he descends with a net retardation of $2.5\,m/s^2$. If he bails out of the plane at a height of $2495\,m$ and $g = 10\,m/s^2$,his velocity on reaching the ground will be .......$m/s$.

A
$5$
B
$10$
C
$15$
D
$20$

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Motion in Straight Line

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Mix Examples-Motion in Straight Line

$A$ particle moving in a straight line covers half the distance with speed $6 \, m/s$. The other half is covered in two equal time intervals with speeds $9 \, m/s$ and $15 \, m/s$ respectively. The average speed of the particle during the motion is: (in $ \, m/s$)

DifficultJEE MAIN 2024

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$Assertion$: $A$ body with constant acceleration always moves along a straight line.
$Reason$: $A$ body with constant acceleration may not speed up.

EasyAIIMS 1998

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$A$ car accelerates from rest with $2 \,m/s^2$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 \,m$ in $20 \,s$. Then, the maximum velocity attained by the car is (in $\,m/s$)

MediumTS EAMCET 2016

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At time $t=0$, a particle leaves the origin and moves in the positive direction of the $X$-axis. If the velocity of the particle varies as $v(t)=v_0(1-t/t_0)$, where $|v_0|=10 \ m/s$ and $t_0=10 \ s$, then the distance covered by the particle during the first $20 \ s$ is: (in $m$)

DifficultTS EAMCET 2021

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The speed-time graph for a body moving along a straight line is shown in the figure. The average acceleration of the body may be .......... $m/s^2$.

Medium

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$A$ parachutist drops freely from an aeroplane for $10\,s$ before the parachute opens. Then he descends with a net retardation of $2.5\,m/s^2$. If he bails out of the plane at a height of $2495\,m$ and $g = 10\,m/s^2$,his velocity on reaching the ground will be .......$m/s$.

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$A$ particle moving in a straight line covers half the distance with speed $6 \, m/s$. The other half is covered in two equal time intervals with speeds $9 \, m/s$ and $15 \, m/s$ respectively. The average speed of the particle during the motion is: (in $ \, m/s$)

$Assertion$: $A$ body with constant acceleration always moves along a straight line. $Reason$: $A$ body with constant acceleration may not speed up.

$A$ car accelerates from rest with $2 \,m/s^2$ on a straight line path and then comes to rest after applying brakes. Total distance travelled by the car is $100 \,m$ in $20 \,s$. Then, the maximum velocity attained by the car is (in $\,m/s$)

At time $t=0$, a particle leaves the origin and moves in the positive direction of the $X$-axis. If the velocity of the particle varies as $v(t)=v_0(1-t/t_0)$, where $|v_0|=10 \ m/s$ and $t_0=10 \ s$, then the distance covered by the particle during the first $20 \ s$ is: (in $m$)

The speed-time graph for a body moving along a straight line is shown in the figure. The average acceleration of the body may be .......... $m/s^2$.

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$Assertion$: $A$ body with constant acceleration always moves along a straight line.
$Reason$: $A$ body with constant acceleration may not speed up.